Question

Умножение дробей: 72х^4\25у^5*(-25у^4\27х^5)= -аb*(-11х^2\3а^2b^2)=

Answer 1

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Вот ответ
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Answer 2

To multiply the given fractions, we can simplify each fraction first and then multiply them together. Let's work through the steps:

1. Simplify the first fraction: (72x^4)/(25y^5) * (-25y^4)/(27x^5)

To simplify, divide the common factors in the numerator with the common factors in the denominator: (72 / 25) * (x^4 / x^5) * (y^4 / y^5)

Further simplification: (72 / 25) * (1 / x) * (1 / y)

2. Simplify the second fraction: -ab * (-11x^2 / 3a^2b^2)

The negative signs cancel out: ab * (11x^2 / 3a^2b^2)

3. Now, multiply the simplified fractions: (72 / 25) * (1 / x) * (1 / y) * ab * (11x^2 / 3a^2b^2)

Now, we can cancel out some common factors: (72 * 11) / (25 * 3) * (1 / x) * (1 / y) * (a / a) * (b / b) * (x^2 / a^2) * (1 / b^2)

Simplifying further: (792 / 75) * (x^2 / (a^2 * y))

Finally, the result is: (792x^2) / (75a^2y)