Question

Найти дискриминант 3x^2+x-11=0

Answer 1

$3x^2+x-11=0\\\\D=b^2-4ac=1^2-4\cdot 3\cdot (-11)=133\\\\x_{1,2}=\frac{-1\pm \sqrt{133}}{6}$

Answer 2

1+4*3*11=133
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Answer 3

To find the discriminant of the quadratic equation $3x^2 + x - 11 = 0$, you can use the formula for the discriminant, which is given by $D = b^2 - 4ac$, where the quadratic equation is in the form $ax^2 + bx + c = 0$.

In the given equation, $a = 3$, $b = 1$, and $c = -11$. Now, let's calculate the discriminant:

$D = (1)^2 - 4 \cdot 3 \cdot (-11)$ $D = 1 + 132$ $D = 133$

So, the discriminant of the equation $3x^2 + x - 11 = 0$ is $133$.