Question

3y-4=3y/7: b/5-2b=-4

Answer 1

Объяснение:

ну вроде так должно быть

Answer 2

To solve the system of equations, let's tackle each equation one by one.

Equation 1: 3y - 4 = 3y/7

Step 1: Get rid of the fraction by multiplying both sides by 7 (the denominator of 3y/7). 7 * (3y - 4) = 7 * (3y/7)

Step 2: Distribute the multiplication on the left side. 21y - 28 = 3y

Step 3: Move all the y terms to one side and the constant terms to the other side. 21y - 3y = 28

Step 4: Combine like terms. 18y = 28

Step 5: Isolate y by dividing both sides by 18. y = 28 / 18 y = 14/9

So the solution for the first equation is y = 14/9.

Now, let's move on to the second equation:

Equation 2: b/5 - 2b = -4

Step 1: Get rid of the fraction by multiplying both sides by 5 (the denominator of b/5). 5 * (b/5 - 2b) = 5 * (-4)

Step 2: Simplify the left side. b - 10b = -20

Step 3: Combine like terms. -9b = -20

Step 4: Isolate b by dividing both sides by -9. b = -20 / -9 b = 20/9 (note that dividing by a negative number flips the inequality)

So the solution for the second equation is b = 20/9.

Therefore, the solution to the system of equations is y = 14/9 and b = 20/9.