Question

8(2y-5)-4(3y-7)-6y=2-y-12

Answer 1

8(2y - 5) - 4(3y-7) - 6y = 2 - y - 12

16у - 40 - 12у + 28 - 6у = 2 - у - 12

-2у - 12  = 2 - у - 12

-2у + у = 2

у = -2

Answer 2

16y-40-12y+28-6y=2-y-12
16y-12y-6y+y=2-12+40-28
-y=2
y=-2

Answer 3

Let's solve the equation step by step:

1. Distribute the numbers outside the parentheses:

8 * (2y - 5) = 16y - 40 4 * (3y - 7) = 12y - 28

2. Rewrite the equation with the distributed terms:

(16y - 40) - (12y - 28) - 6y = 2 - y - 12

3. Now combine like terms on both sides of the equation:

16y - 40 - 12y + 28 - 6y = 2 - y - 12

4. Combine the y terms on the left side of the equation:

(16y - 12y - 6y) - 40 + 28 = 2 - y - 12

Simplify:

-2y - 12 = 2 - y - 12

5. Now, let's isolate the y term on one side of the equation. Add 2y to both sides:

-2y + 2y - 12 = 2 - y - 12 + 2y

Simplify:

-12 = 2 - y

6. Finally, isolate y by subtracting 2 from both sides:

-12 - 2 = 2 - y - 2

Simplify:

-14 = -y

Now, to find the value of y, multiply both sides by -1 (since -(-y) = y):

-1 * -14 = -1 * -y

Simplify:

14 = y

So, the solution to the equation is y = 14.