Question

(4-c)^2+(c+4)(4-c) упростить.

Answer 1

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Answer 2

To simplify the given expression, let's expand and combine like terms:

(4-c)^2 + (c+4)(4-c)

Step 1: Expand (4-c)^2 (4-c)^2 = (4-c)(4-c) = 16 - 4c - 4c + c^2 = 16 - 8c + c^2

Step 2: Expand (c+4)(4-c) (c+4)(4-c) = c(4-c) + 4(4-c) = 4c - c^2 + 16 - 4c

Now let's combine the two terms:

(4-c)^2 + (c+4)(4-c) = (16 - 8c + c^2) + (4c - c^2 + 16 - 4c)

Notice that the terms -8c and +4c cancel each other out, and the terms c^2 and -c^2 also cancel each other out. We are left with:

(4-c)^2 + (c+4)(4-c) = 16 + 16

Finally, add the constants:

(4-c)^2 + (c+4)(4-c) = 32

The simplified expression is 32.