Question

F(x)=4-0,5x f(-1),f(0),f(1),f2

Answer 1

F(x)=4-0,5x

F(-1)=4-5×(-1)=4+5=9; F(0)=4-5×0=4-0=4; F(1)=4-5×1=4-5=-1; F(2)=4-5×2=4-10=-6

Answer 2

To find the values of the function $f(x) = 4 - 0.5x$ at specific points, we simply need to substitute the given values of $x$ into the function. Let's calculate $f(-1)$, $f(0)$, $f(1)$, and $f(2)$:

1. $f(-1)$ $f(-1) = 4 - 0.5 \times (-1)$ $f(-1) = 4 + 0.5$ $f(-1) = 4.5$

2. $f(0)$ $f(0) = 4 - 0.5 \times 0$ $f(0) = 4$

3. $f(1)$ $f(1) = 4 - 0.5 \times 1$ $f(1) = 4 - 0.5$ $f(1) = 3.5$

4. $f(2)$ $f(2) = 4 - 0.5 \times 2$ $f(2) = 4 - 1$ $f(2) = 3$

So, the values of the function $f(x) = 4 - 0.5x$ at $x = -1$, $x = 0$, $x = 1$, and $x = 2$ are $4.5$, $4$, $3.5$, and $3$ respectively.