Question

Решите уравнение (x+3)(− x−2)=0.

Answer 1

(x+3)(-x-2)=0

x+3=0

-x-2=0

x=-3

x=-2

Answer 2

-х^2 -2х-3х-6=0

-х^2-5х-6=0

х^2+5х+6=0

D=25-24=1

x1=-2;    x2= -3

Answer 3

To solve the equation $(x+3)(-x-2) = 0$, we need to find the values of $x$ that make the left-hand side of the equation equal to zero. In other words, we are looking for the values of $x$ that satisfy the equation when it's set to zero.

To do that, we can use the zero-product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be zero.

So, we have two factors: $x+3$ and $-x-2$. We set each factor to zero and solve for $x$:

1. Setting $x+3$ to zero: $x + 3 = 0$

Subtract 3 from both sides: $x = -3$

2. Setting $-x-2$ to zero: $-x - 2 = 0$

Add 2 to both sides: $-x = 2$

Multiply both sides by -1 (to solve for $x$): $x = -2$

So, the solutions to the equation are $x = -3$ and $x = -2$.