Question

Cos a=-0,6 найти sin a , tg a. П/2≤a≤Π

Answer 1

Решение во вложении

Answer 2

cos a=-0,6  sin a=?  tg a=?  π/2≤a≤π (вторая четверть) sin a>0  tg a<0  

sin a=√(1-cos² a)=√(1-(-0,6 )²)=√(1-0,36)=√0,64=+/-0,8.

sin a=0,8=4/5.

tg a=sin a/cos a=0,8/(-0,6)=8/6=-4/3.

Ответ: sin a=4/5    tg a=-4/3.

Answer 3

To find the values of sin(a) and tan(a) when a = -0.6, we need to know whether the value of 'a' is given in radians or degrees. Since the given range is specified in radians (π/2 ≤ a ≤ π), I'll assume that 'a' is given in radians.

1. Finding sin(a): We can use the trigonometric identity: sin(a) = -sin(-a) for any angle 'a'.

a = -0.6 (given)

Since -a = 0.6, we can find sin(a) as follows: sin(a) = -sin(-0.6)

Now, we need to find sin(0.6). Since π/2 ≤ 0.6 ≤ π, we are in the second quadrant where the sine function is positive.

sin(0.6) ≈ 0.5646424734 (approximately)

Therefore, sin(a) ≈ -0.5646424734 (approximately)

2. Finding tan(a): We can use the trigonometric identity: tan(a) = -tan(-a) for any angle 'a'.

a = -0.6 (given)

Since -a = 0.6, we can find tan(a) as follows: tan(a) = -tan(-0.6)

Now, we need to find tan(0.6). Since π/2 ≤ 0.6 ≤ π, we are in the second quadrant where the tangent function is negative.

tan(0.6) ≈ -0.68413680834 (approximately)

Therefore, tan(a) ≈ -(-0.68413680834) ≈ 0.68413680834 (approximately)

So, the approximate values are: sin(a) ≈ -0.5646 tan(a) ≈ 0.6841