Question

X²+3x-18 тричлен решите PLEASE

Answer 1

По теореме Виета сумма корней трехчлена равна -3, произведение равно -18

Этому удовлетворяют числа -6 и 3

Ответ: -6; 3

Answer 2

x²+3x-18 =0

D=3²+4*18=9+72=81

x₁=(-3+9)/2= 3

x₂=(-3-9)/2= -6

если надо разложить его на множители, то это будет выглядеть так

x²+3x-18 =(x-3)*(x+6)

Answer 3

To solve the quadratic equation $x^2 + 3x - 18 = 0$, we can use the quadratic formula. The quadratic formula states that for an equation of the form $ax^2 + bx + c = 0$, the solutions for $x$ can be found using the following formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In our case, $a = 1$, $b = 3$, and $c = -18$. Plugging these values into the formula, we get:

$x = \frac{-3 \pm \sqrt{3^2 - 4 \cdot 1 \cdot (-18)}}{2 \cdot 1}$

$x = \frac{-3 \pm \sqrt{9 + 72}}{2}$

$x = \frac{-3 \pm \sqrt{81}}{2}$

Now, we have two solutions:

1. $x = \frac{-3 + \sqrt{81}}{2} = \frac{-3 + 9}{2} = \frac{6}{2} = 3$

2. $x = \frac{-3 - \sqrt{81}}{2} = \frac{-3 - 9}{2} = \frac{-12}{2} = -6$

So, the solutions to the quadratic equation $x^2 + 3x - 18 = 0$ are $x = 3$ and $x = -6$.