Question

5 2 3 4 3 2 2 3 1 вычислить опредилитель

Answer 1

Det A = 
|523|
|432|
|231| 
= 5·3·1 + 2·2·2 + 3·4·3 - 3·3·2 - 5·2·3 - 2·4·1 = 15 + 8 + 36 - 18 - 30 - 8 = 3

Answer 2

To calculate the determinant of a 3x3 matrix using the given values, we need to arrange them in a matrix form and apply the formula for calculating the determinant. The matrix will look like this:

Copy code
| 5  2  3 |
| 4  3  2 |
| 2  3  1 |

The formula to find the determinant of a 3x3 matrix is:

det(A) = a(ei − fh) − b(di − fg) + c(dh − eg)

where the matrix is given as: | a b c | | d e f | | g h i |

Now, substitute the values from the matrix: det(A) = 5(3 * 1 - 2 * 3) - 2(4 * 1 - 2 * 3) + 3(4 * 3 - 2 * 3)

Now, perform the calculations: det(A) = 5(3 - 6) - 2(4 - 6) + 3(12 - 6) det(A) = 5(-3) - 2(-2) + 3(6) det(A) = -15 + 4 + 18 det(A) = 7

So, the determinant of the given 3x3 matrix is 7.