Question

(x-4)^2-x(x-2) при x = -1,2

Answer 1

(x-4)^2-x(x-2)= х^2-8х+16-х^2+2х= 16-6х= 16-6×(-1.2)= 16+7.2= 23.2

Answer 2

Ответ:

23,2

Пошаговое объяснение

(x - 4)² - x(x - 2)  = x² - 8x + 16 - x² + 2x = 16 - 6x

При x = -1,2

16 - 6 * (-1,2) = 16 + 7,2 = 23,2

_______________________

(x - 4)² раскрыли с помощью формулы квадрата разности:

(a - b)² = a² - 2ab + b²

Answer 3

To find the value of the expression (x-4)^2 - x(x-2) for the given values of x, which are x = -1 and x = 2, we simply substitute these values into the expression and calculate the result.

1. For x = -1:

(x-4)^2 - x(x-2) = (-1-4)^2 - (-1)(-1-2) = (-5)^2 - (-1)(-3) = 25 - 3 = 22

2. For x = 2:

(x-4)^2 - x(x-2) = (2-4)^2 - 2(2-2) = (-2)^2 - 2(0) = 4 - 0 = 4

So, when x = -1, the expression evaluates to 22, and when x = 2, the expression evaluates to 4.