Question

(3x^2-2,5y)^2=9x^4-?+6,25y^2 найдите"?" Пожалуйста

Answer 1

(3x^2-2,5y)^2=9x^4+6,25y^2-15x^2y

Ответ:15x^2y.

(3x^2-2,5y)^2 - формула сокращенного умножения

(a-b)^2=a^2+b^2-2ab

Answer 2

To find the value of "?", let's expand the given expression:

(3x^2 - 2.5y)^2 = 9x^4 - ? + 6.25y^2

To expand the left side, we use the formula for squaring a binomial:

(a - b)^2 = a^2 - 2ab + b^2

In this case, a = 3x^2 and b = 2.5y:

(3x^2 - 2.5y)^2 = (3x^2)^2 - 2(3x^2)(2.5y) + (2.5y)^2 = 9x^4 - 15x^2y + 6.25y^2

Now we can compare it with the right side of the equation:

9x^4 - ? + 6.25y^2 = 9x^4 - 15x^2y + 6.25y^2

Since the two expressions are equal, we can find the missing value by equating the corresponding terms:

? = 15x^2y

So the value of "?" is 15x^2y.