Question

(2x-1)(2x+1)-(2x+3) во второй степени

Answer 1

=4x²-1-4х²-12х-9= -12х-10

Answer 2

To find the square of the expression (2x-1)(2x+1)-(2x+3), we need to multiply the expression by itself (square it). Let's break it down step by step:

Step 1: Expand the expression (2x-1)(2x+1) (2x-1)(2x+1) = 2x * 2x + 2x * 1 - 1 * 2x - 1 * 1 = 4x^2 + 2x - 2x - 1 = 4x^2 - 1

Step 2: Now, square the result from Step 1. (4x^2 - 1)^2 = (4x^2 - 1) * (4x^2 - 1)

To expand this square, we can use the FOIL method (First, Outer, Inner, Last): = 4x^2 * 4x^2 + 4x^2 * (-1) - 1 * 4x^2 - 1 * (-1)

= 16x^4 - 4x^2 - 4x^2 + 1

Step 3: Combine like terms: = 16x^4 - 8x^2 + 1

So, the square of the expression (2x-1)(2x+1)-(2x+3) is 16x^4 - 8x^2 + 1.