Question

X=-0,8. (6x-1)^2-(10x+3)(10x-3)+(8x+1)^2

Answer 1

Ответ:  $7.8$ .

Объяснение:

Упростим выражение:

$(6x-1)^2-(10x+3)(10x-3)+(8x+1)^2 = \\= (36x^2-12x+1)-(100x^2-9)+(64x^2+16x+1)=\\= 36x^2-12x+1-100x^2+9+64x^2+16x+1=\\= 4x+11.$

Подставим вместо $x$ число $-0.8$ :

$4x+11=4*(-0.8)+11=-3.2+11 =7.8\;.$

Answer 2

To simplify the expression, let's substitute x with -0.8 and perform the calculations step by step.

x = -0.8

Substituting x in the expression:

(6x - 1)^2 - (10x + 3)(10x - 3) + (8x + 1)^2

= (6(-0.8) - 1)^2 - (10(-0.8) + 3)(10(-0.8) - 3) + (8(-0.8) + 1)^2

= (-4.8 - 1)^2 - (-8 + 3)(-8 - 3) + (-6.4 + 1)^2

= (-5.8)^2 - (-5)(-11) + (-5.4)^2

= 33.64 - 55 + 29.16

= 63.8 - 55

= 8.8

Therefore, when x = -0.8, the value of the expression (6x-1)^2 - (10x+3)(10x-3) + (8x+1)^2 is 8.8.