Question

3(х-2)=8(2х+1)9=93(х-5)+8=175(х-1)-4(х-2)=10​

Answer 1

Ответ:

надеюсь помогла как надо

Answer 2

To solve the given equations, let's go through them one by one:

1. 3(x-2) = 8(2x+1)

First, distribute the multiplication on both sides:

3x - 6 = 16x + 8

Now, isolate the variable x on one side of the equation. To do this, move the terms containing x to one side and constants to the other side:

3x - 16x = 8 + 6

Combine like terms:

-13x = 14

Finally, divide both sides by -13 to solve for x:

x = 14 / (-13) x = -1.0769 (approximately)

2. 9(x-5) + 8 = 17

Distribute the multiplication on the left side:

9x - 45 + 8 = 17

Combine constants:

9x - 37 = 17

Now, isolate the variable x by moving the constant term to the other side:

9x = 17 + 37 9x = 54

Finally, divide both sides by 9 to solve for x:

x = 54 / 9 x = 6

3. 5(x-1) - 4(x-2) = 10

Distribute the multiplication on both sides:

5x - 5 - 4x + 8 = 10

Combine like terms:

x + 3 = 10

Isolate the variable x by moving the constant term to the other side:

x = 10 - 3 x = 7

So the solutions to the given equations are:

x = -1.0769, 6, and 7.