Question

15-(3х-1)=40 8х-(2х+4)=2(3х-2)3(2х-1)-5(7-х=8(1-х)-3(х+5)​

Answer 1

6x-3-35+5x=8-8x-3x-15

6x+5x+8x+3x=8-15+3+35

22x=31

x=31/22= 1 9/22 (одна целая. девять двадцать вторых.)

(P.S. напиши какой ответ у тебя. Сверим)))

Answer 2

Let's solve each equation step by step:

1. 15 - (3x - 1) = 40

First, distribute the negative sign inside the parentheses:

15 - 3x + 1 = 40

Now, combine like terms:

16 - 3x = 40

Next, isolate the term with 'x' on one side of the equation. Subtract 16 from both sides:

-3x = 24

Finally, divide both sides by -3 to solve for 'x':

x = -24 / -3 x = 8

2. 8x - (2x + 4) = 2(3x - 2)

First, distribute the negative sign inside the parentheses:

8x - 2x - 4 = 6x - 4

Next, combine like terms:

6x - 4 = 6x - 4

The equation is an identity, meaning it is true for all values of 'x'. There are infinitely many solutions, and 'x' can take any real value.

3. 3(2x - 1) - 5(7 - x) = 8(1 - x) - 3(x + 5)

Let's simplify each side of the equation step by step:

First, distribute the coefficients:

6x - 3 - 35 + 5x = 8 - 8x - 3x - 15

Combine like terms on each side:

11x - 38 = -11x - 10

Now, get all 'x' terms on one side and constants on the other:

11x + 11x = -10 + 38

Combine 'x' terms:

22x = 28

Finally, isolate 'x' by dividing both sides by 22:

x = 28 / 22 x = 14 / 11 x ≈ 1.2727

So, the solution for this equation is approximately x = 1.2727.