Question

Найдите A+B и B-A если A= a^5-5a^4+11; B= -3+6a^4-5a^5

Answer 1

Ответ:

Решение на фото :)

Объяснение:

Answer 2

To find the values of A + B and B - A, we need to substitute the given expressions for A and B into the corresponding expressions and then perform the arithmetic operations. Let's do that:

Given: A = a^5 - 5a^4 + 11 B = -3 + 6a^4 - 5a^5

1. A + B: A + B = (a^5 - 5a^4 + 11) + (-3 + 6a^4 - 5a^5)

Now, combine like terms: A + B = (a^5 - 5a^5) + (6a^4 - 5a^4) + (11 - 3)

Simplify: A + B = -4a^5 + a^4 + 8

2. B - A: B - A = (-3 + 6a^4 - 5a^5) - (a^5 - 5a^4 + 11)

Now, distribute the negative sign: B - A = -3 + 6a^4 - 5a^5 - a^5 + 5a^4 - 11

Combine like terms: B - A = (-5a^5 - a^5) + (6a^4 + 5a^4) + (-3 - 11)

Simplify: B - A = -6a^5 + 11a^4 - 14

So, the values of A + B and B - A are: A + B = -4a^5 + a^4 + 8 B - A = -6a^5 + 11a^4 - 14