Question

26а^5в^5делить 39а^7в^410mn-25n делить 5mnx^2-16делить 2x+8​

Answer 1

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См фотку

Answer 2

To simplify the expression, let's break it down step by step:

Step 1: Simplify the first fraction. $\frac{26a^5b^5}{39a^7b^4}$

To simplify the fraction, cancel out common factors from the numerator and denominator: $\frac{26}{39} \cdot \frac{a^5}{a^7} \cdot \frac{b^5}{b^4}$

Step 2: Simplify each part separately. $\frac{26}{39} = \frac{2 \cdot 13}{3 \cdot 13} = \frac{2}{3}$

For the exponents, remember that when you divide like bases, you subtract the exponents: $a^5 \div a^7 = a^{5-7} = a^{-2} = \frac{1}{a^2}$ $b^5 \div b^4 = b^{5-4} = b^1 = b$

Putting it all together: $\frac{26a^5b^5}{39a^7b^4} = \frac{2}{3} \cdot \frac{1}{a^2} \cdot b = \frac{2b}{3a^2}$

Step 3: Simplify the second fraction. $\frac{10mn-25n}{5mnx^2-16}$

First, factor out the common term "n" from the numerator: $n(10m-25)$

Factor out the common term "5" from the denominator: $5mn(x^2-\frac{16}{5})$

Step 4: Simplify the expression further. $\frac{n(10m-25)}{5mn(x^2-\frac{16}{5})}$

Now, cancel out the common factors in the numerator and denominator: $\frac{10m-25}{5x^2-\frac{16}{5}}$

Step 5: Further simplify the fraction. $\frac{10m-25}{5x^2-\frac{16}{5}}$

Factor out "5" from the numerator and $\frac{1}{5}$ from the denominator: $\frac{5(2m-5)}{5(x^2-\frac{16}{5})} = \frac{2m-5}{x^2-\frac{16}{5}}$

Step 6: Simplify the last fraction. $\frac{2x+8}{2x+8} = 1$

Now, putting it all together: $\frac{26a^5b^5}{39a^7b^4} \div \frac{10mn-25n}{5mnx^2-16} \div \frac{2x+8}{2x+8} = \frac{2b}{3a^2} \div \frac{2m-5}{x^2-\frac{16}{5}}$