Question

(3x-2)(x+4)=(3x+15)(x-1)

Answer 1

(3x-2)(x+4)=(3x+15)(x-1)

3х²+12х-2х-8=3х²-3х+15х-15

3х²+10х-8=3х²+12х-15

-2х=-7

х=7/2=3,5

Answer 2

To solve the given equation, we'll start by expanding both sides and then simplifying the expression to find the value of 'x.'

Expanding the left-hand side (LHS): (LHS) = (3x - 2)(x + 4) (LHS) = 3x * x + 3x * 4 - 2 * x - 2 * 4 (LHS) = 3x^2 + 12x - 2x - 8 (LHS) = 3x^2 + 10x - 8

Expanding the right-hand side (RHS): (RHS) = (3x + 15)(x - 1) (RHS) = 3x * x + 3x * (-1) + 15 * x - 15 * 1 (RHS) = 3x^2 - 3x + 15x - 15 (RHS) = 3x^2 + 12x - 15

Now that we have expanded both sides, we can set them equal to each other since they represent the same equation:

3x^2 + 10x - 8 = 3x^2 + 12x - 15

Next, we can eliminate the common terms (3x^2) from both sides:

10x - 8 = 12x - 15

Now, let's isolate the variable 'x' on one side of the equation. We'll do this by moving all the terms containing 'x' to one side and the constant terms to the other side:

10x - 12x = -15 + 8

-2x = -7

Finally, solve for 'x' by dividing both sides by -2:

x = (-7) / (-2)

x = 7/2

So, the solution to the equation is:

x = 7/2 or x = 3.5