Question

Найти производную функции: y=tg+1/ x

Answer 1

Ответ:У↓- производная

У↓=( tgХ+1/Х)↓= 1/cos²Х - 1/Х²

Объяснение:

Answer 2

To find the derivative of the function $y = \tan(x) + \frac{1}{x}$, we'll need to apply the rules of differentiation. The derivative of $\tan(x)$ with respect to $x$ is $\sec^2(x)$, and the derivative of $\frac{1}{x}$ is $-\frac{1}{x^2}$.

Therefore, the derivative of $y$ with respect to $x$ is:

$\frac{dy}{dx} = \sec^2(x) - \frac{1}{x^2}$

So the final result is $\frac{dy}{dx} = \sec^2(x) - \frac{1}{x^2}$.