Question

Решить уравнение: (5-x)^2-x(2,5+x)=0

Answer 1

$(5-x)^{2} -x(2,5+x)=0$

$25-10x+x^{2}-2,5x-x^{2}=0$

$-12,5x=-25$

$x=2$

Ответ: 2

Answer 2

Ответ:

х=2

Объяснение:

(5-x)²-x(2,5+x)=0

25-10х+х²×(2,5+х)=0

15-10х+х²-2,5х-х²=0

25-10х-2,5х=0

25-12,5х=0

-12,5х= -25

х=2

Answer 3

To solve the equation (5-x)^2 - x(2.5+x) = 0, follow these steps:

Step 1: Expand the equation. Step 2: Move all terms to one side to set the equation to zero. Step 3: Factor the quadratic equation. Step 4: Solve for the value(s) of x.

Let's go through each step:

Step 1: Expand the equation (5-x)^2 - x(2.5+x) = 0 (5-x)(5-x) - (2.5x + x^2) = 0 (25 - 10x + x^2) - (2.5x + x^2) = 0

Step 2: Move all terms to one side 25 - 10x + x^2 - 2.5x - x^2 = 0 25 - 10x - 2.5x = 0

Step 3: Combine like terms 25 - 12.5x = 0

Step 4: Solve for x Subtract 25 from both sides: -12.5x = -25

Now, divide both sides by -12.5 to isolate x: x = -25 / -12.5

x = 2

So, the solution to the equation is x = 2.