Question

-4x*(x-1) вместо x вставить одинаковые числа чтобы в ответе получить 1

Answer 1

$- 4x(x - 1) = 1 \\ - 4 {x}^{2} + 4x - 1 = 0 \\ 4 {x}^{2} - 4x + 1 = 0 \\ D = 16 - 4 \times 4 \times 1 = 0 \\ x = \frac{ - ( - 4)}{2 \times 4} = \frac{1}{2}$

Ответ: 0,5

Answer 2

To make the expression -4x*(x-1) equal to 1, you need to substitute the value of x with the same number. Let's call this number 'a'. The equation would be:

-4a*(a-1) = 1

Now, we need to solve for 'a':

Step 1: Expand the expression: -4a*(a-1) = -4a^2 + 4a

Step 2: Set the equation equal to 1: -4a^2 + 4a = 1

Step 3: Move all terms to one side to form a quadratic equation: -4a^2 + 4a - 1 = 0

Step 4: Solve the quadratic equation. You can use the quadratic formula: The quadratic formula is given by: x = (-b ± √(b^2 - 4ac)) / 2a

In our case, a = -4, b = 4, and c = -1.

x = (-(4) ± √(4^2 - 4*(-4)(-1))) / 2(-4) x = (-4 ± √(16 - 16)) / -8 x = (-4 ± √0) / -8

Since the discriminant (the term inside the square root) is zero, the quadratic equation has a single real root.

Step 5: Calculate the root: x = (-4 + 0) / -8 x = 0 / -8 x = 0

So, when you substitute x with 0, the expression -4x*(x-1) will be equal to 1.