Question

2x+8y=1 3x+5y=16 3x-y=10

Answer 1

Ответ:1)2х=1-8у;x=1/2 -4y y належить R

2)3x=16-5y ;x=16/3-5/3y

3)3x=10+y ;x=10/3+1/3y

Объяснение:

Answer 2

To solve the system of equations:

1. 2x + 8y = 1
2. 3x + 5y = 16
3. 3x - y = 10

We can use the method of elimination or substitution. Let's use the elimination method to solve the system.

Step 1: Multiply the third equation by 8 to make the y-coefficient in the first equation and the third equation the same. This will allow us to eliminate y when we add the equations together.

3x - y = 10 Multiply by 8: 8(3x - y) = 8 * 10 24x - 8y = 80

Now the system becomes:

1. 2x + 8y = 1
2. 3x + 5y = 16
3. 24x - 8y = 80

Step 2: Add the first and third equations to eliminate y.

(2x + 8y) + (24x - 8y) = 1 + 80 26x = 81

Step 3: Solve for x.

x = 81 / 26 x ≈ 3.1154

Step 4: Now, substitute the value of x back into one of the original equations to solve for y. Let's use the second equation.

3x + 5y = 16 3(3.1154) + 5y = 16 9.3462 + 5y = 16 5y = 16 - 9.3462 5y = 6.6538 y = 6.6538 / 5 y ≈ 1.3308

So the solution to the system of equations is approximately x ≈ 3.1154 and y ≈ 1.3308.