Question

X²+4x-77=0 решите без корней​

Answer 1

Ответ:

Объяснение:

x²+4x-77=0

x²+4x+7x-7x-77=0

x²+11x-7x-77=0

x*(x+11)-7*(x+11)=0

(x+11)*(x-7)=0

x₁=-11     x₂=7.

Answer 2

To determine whether the equation $x^2 + 4x - 77 = 0$ has real roots (solutions) or not, we can use the discriminant. The discriminant ($\Delta$) is given by the formula $\Delta = b^2 - 4ac$, where $a$, $b$, and $c$ are the coefficients of the quadratic equation $ax^2 + bx + c = 0$.

In this case, $a = 1$, $b = 4$, and $c = -77$. Let's calculate the discriminant:

$\Delta = b^2 - 4ac = 4^2 - 4 \cdot 1 \cdot (-77) = 16 + 308 = 324$.

Since the discriminant is positive ($\Delta > 0$), the quadratic equation has two distinct real roots.

So, there are real roots for the given equation $x^2 + 4x - 77 = 0$.