Question

При каких значениях p двучлен 10p+2 принимает значения большие, чем 1 ?

Answer 1

10p+2 >1

10p>-1

p>-0.1

Ответ р>-0.1

Answer 2

To find the values of p for which the expression 10p + 2 is greater than 1, we can set up the inequality:

10p + 2 > 1

Now, let's solve for p:

Subtract 2 from both sides of the inequality:

10p > 1 - 2

10p > -1

Finally, divide both sides by 10:

p > -1/10

So, the values of p for which the expression 10p + 2 is greater than 1 are all real numbers greater than -1/10. In interval notation, this can be written as:

p ∈ (-1/10, +∞)

This means that any value of p greater than -1/10 will make the expression 10p + 2 greater than 1.