Question

(9t−...)(9t+...) = 81t2−100

Answer 1

Ответ:

(9t−10)(9t+10)= 81t2−100

Объяснение:

Answer 2

To solve this problem, let's use the difference of squares formula:

(a - b)(a + b) = a^2 - b^2

In this case, a = 9t and b is a missing term. We are given that (9t - ...)(9t + ...) = 81t^2 - 100.

Since 81t^2 - 100 is already in the form of a difference of squares (a^2 - b^2), we can find the missing term by equating the corresponding components.

a^2 = 81t^2 b^2 = 100

Now we can solve for a and b:

a = √(81t^2) = 9t b = √100 = 10

So, the missing terms are 10 and -10, and the original expression is:

(9t - 10)(9t + 10) = 81t^2 - 100

Thus, the missing terms are 10 and -10.