Question

3x²- 12= bx²- 9b= 2p²- 98a²= -3a³- 3ab²=

Answer 1

Ответ:

A) 3(x³ -4)

b) b(x²-9)=b(x-3)(x+3)

в) 2(p²-49a²)=2(p-7a)(p+7a)

г) 3a(a²+в²)

Объяснение:

Answer 2

Ответ:

Объяснение:

3(Х-4)

В(х2-9)

2(Р2-49А2)

-3А( А2+В2)

Answer 3

To solve these equations for their respective variables, we need to isolate the variables on one side of the equation. Let's solve each equation step by step:

1. 3x² - 12 = 0 To solve for x, we'll first add 12 to both sides and then divide by 3 to isolate x: 3x² = 12 x² = 12 / 3 x² = 4 x = ±√4 x = ±2

So, the solutions for x are x = 2 and x = -2.

2. bx² - 9b = 0 We can factor out 'b' from the equation: b(x² - 9) = 0

Now, set each factor to zero to solve for 'x': b = 0 x² - 9 = 0

For the first equation, b = 0. For the second equation, solve for 'x': x² = 9 x = ±√9 x = ±3

So, the solutions for the second equation are x = 3 and x = -3.

3. 2p² - 98a² = 0 We can factor out '2' from the equation: 2(p² - 49a²) = 0

Now, set each factor to zero to solve for 'p': p² - 49a² = 0

To further solve for 'p', you would need additional information or equations involving 'p' and 'a'.

4. -3a³ - 3ab² = 0 We can factor out '3a' from the equation: 3a(-a² - b²) = 0

Now, set each factor to zero to solve for 'a': 3a = 0 -a² - b² = 0

For the first equation, 3a = 0, we get a = 0.

For the second equation, -a² - b² = 0, we don't have enough information to solve for 'a' or 'b' without additional equations or context.