Question

121-(а+3)^2- решить уравнение

Answer 1

Ответ:

8

-14

Объяснение:

a+3=11

a=8

a+3=-11

a=-14

Answer 2

To solve the equation 121 - (а + 3)^2 = 0, follow these steps:

Step 1: Expand the squared term. Step 2: Combine like terms. Step 3: Isolate the variable and solve for 'a'.

Let's proceed with the steps:

Step 1: Expand the squared term. (а + 3)^2 = (а + 3)(а + 3) = а^2 + 6а + 9

Step 2: Combine like terms. 121 - (а + 3)^2 = 121 - (а^2 + 6а + 9) = 121 - а^2 - 6а - 9 = 112 - а^2 - 6а

Step 3: Isolate the variable and solve for 'a'. To solve the equation, set it equal to zero: 112 - а^2 - 6а = 0

Now, we have a quadratic equation. To solve it, let's make it equal to zero: а^2 + 6а - 112 = 0

To solve the quadratic equation, you can either factor it or use the quadratic formula. In this case, factoring is a bit challenging, so let's use the quadratic formula:

The quadratic formula is given by: a = (-b ± √(b^2 - 4ac)) / 2a

In our equation, a^2 + 6a - 112 = 0, we have: a = (-6 ± √(6^2 - 4 * 1 * (-112))) / 2 * 1 a = (-6 ± √(36 + 448)) / 2 a = (-6 ± √484) / 2 a = (-6 ± 22) / 2

Now, calculate both possible values of 'a':

1. a = (-6 + 22) / 2 a = 16 / 2 a = 8

2. a = (-6 - 22) / 2 a = -28 / 2 a = -14

So, the two solutions to the equation are a = 8 and a = -14.