Question

7x-2x^2 =6 как решить?

Answer 1

Ответ:

$x_{1,2}=\frac{7^+_-\sqrt{97}}{4}=$

Объяснение:

$7x-2x^2=6$

$-2x^2+7x-6=0$

$ax^2+bx+c=0$

$a=-2;b=7;c=-6$

$D=b^2-4ac$

$D=7^2-4*(-2)*(-6)=49+48=97$

$x_{1,2}=\frac{-b^+_-\sqrt{D}}{2a}$

$x_{1,2}=\frac{-7^+_-\sqrt{97}}{2*(-2)}=\frac{7^-_+\sqrt{97}}{4}$

Answer 2

To solve the equation 7x - 2x^2 = 6, you need to find the values of x that make the equation true. Here's how you can do it:

Step 1: Rewrite the equation in standard form: -2x^2 + 7x - 6 = 0

Step 2: To solve a quadratic equation of the form ax^2 + bx + c = 0, you can use the quadratic formula:

The quadratic formula is given by: x = (-b ± √(b^2 - 4ac)) / 2a

In this case, a = -2, b = 7, and c = -6.

Step 3: Substitute the values into the quadratic formula and calculate the solutions:

x = (-(7) ± √(7^2 - 4(-2)(-6))) / 2(-2) x = (-7 ± √(49 - 48)) / -4 x = (-7 ± √1) / -4 x = (-7 + 1) / -4 or x = (-7 - 1) / -4 x = -6 / -4 or x = -8 / -4 x = 3/2 or x = 2

So, the solutions to the equation are x = 3/2 and x = 2.