Question

(x-6)^2+(y+1)^2=2^2=4 - правильно-ли решено? Записать уравнение окружности с центром в точке М и радиусом r, если М (6; −1), r =4.

Answer 1

Ответ:

(x-6)²+( y+1)²=16

радиус в уравнении равен квадрату,исправьте 4 на 4²=16

Answer 2

There is a small mistake in your statement. The equation you provided has an extra "=" sign after "2^2," which should not be there. The correct equation for a circle with center M(6, -1) and radius r = 4 is:

(x - 6)^2 + (y + 1)^2 = 4^2

This equation represents a circle with its center at point (6, -1) and a radius of 4 units.