Question

Розкласти на множники 1)25a²b²-0,36 2)1+64a³ 3)5c(в п'ятій)-5с³

Answer 1

Ответ:

Объяснение:

(5ab-0,6)(5ab+0,6)

(1+4a)(1-4a+16a²)

5c³(c²-1)= 5c³(c-1)(c+1)

Answer 2

1. 25a²b² - 0.36:

To factor this expression, we can notice that 0.36 is a perfect square (0.36 = 0.6²). So we have:

25a²b² - 0.36 = 25a²b² - (0.6)²

Now, we can use the formula for the difference of squares, which states that a² - b² = (a + b)(a - b). In this case, let's consider a = 5ab and b = 0.6:

25a²b² - (0.6)² = (5ab + 0.6)(5ab - 0.6)

Therefore, the expression 25a²b² - 0.36 can be factored as (5ab + 0.6)(5ab - 0.6).

2. 1 + 64a³:

This expression represents the sum of two terms, but it cannot be factored further. It is already in its simplest form.

3. 5c⁵ - 5c³:

We can notice that both terms have a common factor of 5c³. Factoring out this common factor, we get:

5c⁵ - 5c³ = 5c³(c² - 1)

Now, we can further factor the expression c² - 1 using the difference of squares formula:

5c³(c² - 1) = 5c³(c + 1)(c - 1)

Therefore, the expression 5c⁵ - 5c³ can be factored as 5c³(c + 1)(c - 1).