Question

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Answer 1

Ответ: x∈(-∞;+∞).

Объяснение:

$x^{2} +10x+26>0\\x^{2} +10\\x+25+1>0\\x^{2}+2*x*5+5^{2} +1>0\\ (x-5)^{2} +1>0$

Так как (х-5)²≥0,    ⇒    (х-5)²+1>0

x∈(-∞;+∞).

Answer 2

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