Question

F(x)= 2x2+13x при каких x f(x) =7

Answer 1

Ответ: смотри во вложении

Объяснение:

Answer 2

To find the values of x for which f(x) equals 7, we need to solve the equation:

2x^2 + 13x = 7

Let's rearrange the equation and set it equal to zero:

2x^2 + 13x - 7 = 0

Now we have a quadratic equation in standard form. We can solve it by factoring, completing the square, or using the quadratic formula. Let's use the quadratic formula in this case.

The quadratic formula states that for an equation in the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

In our equation, a = 2, b = 13, and c = -7. Substituting these values into the formula, we get:

x = (-13 ± √(13^2 - 4 * 2 * -7)) / (2 * 2)

Simplifying further:

x = (-13 ± √(169 + 56)) / 4

x = (-13 ± √225) / 4

x = (-13 ± 15) / 4

Now we have two possible solutions:

x1 = (-13 + 15) / 4 = 2 / 4 = 0.5

x2 = (-13 - 15) / 4 = -28 / 4 = -7

Therefore, the values of x for which f(x) equals 7 are x = 0.5 and x = -7.