Question

(x+b−2z)(b−x)−(b+z−2x)⋅(b−z)+(z+x−2b)(x−z)+14​

Answer 1

Ответ:

всё пере умножаем и сокращается

Answer 2

Ответ:

-2bz+z²+xz-2z-2x+4b+14

Answer 3

To simplify the expression, let's expand and combine like terms:

(x + b - 2z)(b - x) - (b + z - 2x)(b - z) + (z + x - 2b)(x - z) + 14

Expanding the first term:

(x + b - 2z)(b - x) = (xb - x^2 + bb - bx - 2zb + 2zx)

Expanding the second term:

(b + z - 2x)(b - z) = (bb - bz + zb - zz - 2xb + 2xz)

Expanding the third term:

(z + x - 2b)(x - z) = (zx - zz + xb - xz - 2bx + 2bz)

Combining like terms:

(xb - x^2 + bb - bx - 2zb + 2zx) - (bb - bz + zb - zz - 2xb + 2xz) + (zx - zz + xb - xz - 2bx + 2bz) + 14

Simplifying further:

xb - x^2 + bb - bx - 2zb + 2zx - bb + bz - zb + zz + 2xb - 2xz + zx - zz + xb - xz - 2bx + 2bz + 14

Combining like terms again:

• x^2 + bb - x^2 - 2zb + 2xb + 2zx + bz + zz - 2xz + zx - xz - 2bx + 2bz + 14

Simplifying further:

-2x^2 + 3xb - 2zb + 3zx + bz + zz - 2xz - 2bx + 2bz + 14

So the simplified expression is:

-2x^2 + 3xb - 2zb + 3zx + bz + zz - 2xz - 2bx + 2bz + 14