Question

{ 2x + 5y = 15 3x + 8y = −1

Answer 1

Ответ:

x = 125

y = -47

Объяснение:

2x + 5y = 15

3x + 8y = −1

Умножим 1-ое уравнение на 3, а 2-ое на -2

6x + 15y = 45

-6x - 16y = 2

сложим

-y = 47

y = -47

x = (15 - 5y)/2 = (15 + 235)/2 = 125

Answer 2

It looks like you've provided a system of two linear equations with two variables, x and y. This system can be solved to find the values of x and y that satisfy both equations. There are various methods to solve such systems, such as substitution, elimination, or using matrices.

Let's solve this system using the elimination method:

Given the system of equations:

1. $2x + 5y = 15$
2. $3x + 8y = -1$

We can start by multiplying both sides of equation 1 by 3 and equation 2 by 2 to make the coefficients of x in both equations equal:

3 * $2x + 5y = 15$ => $6x + 15y = 45$ 2 * $3x + 8y = -1$ => $6x + 16y = -2$

Now, subtract the modified equation 2 from the modified equation 1 to eliminate x:

$(6x + 15y) - (6x + 16y) = 45 - (-2)$ $-y = 47$

Dividing both sides by -1: $y = -47$

Now that we have the value of y, we can substitute it back into one of the original equations to solve for x. Let's use equation 1:

$2x + 5(-47) = 15$ $2x - 235 = 15$ $2x = 250$ $x = 125$

So, the solution to the system of equations is $x = 125$ and $y = -47$.