Question

X^2+10y^2+4y-6xy+4=0 x*y=?

Answer 1

Ответ:

фото

лалалалалллалалалалалалалалалала

12

Answer 2

To find the value of xy, we need to solve the given quadratic equation for y in terms of x and then calculate the product xy. The equation is:

x^2 + 10y^2 + 4y - 6xy + 4 = 0

To solve for y, we'll treat this equation as a quadratic equation in y. Rearrange the terms:

10y^2 + (4 - 6x)y + x^2 + 4 = 0

This is a quadratic equation in y. We can solve it using the quadratic formula:

y = (-b ± √(b^2 - 4ac)) / 2a

In this case, a = 10, b = 4 - 6x, and c = x^2 + 4. Plugging these values into the formula:

y = (-(4 - 6x) ± √((4 - 6x)^2 - 4 * 10 * (x^2 + 4))) / (2 * 10)

Simplify the equation:

y = (6x - 4 ± √(36x^2 - 48x + 16 - 40x^2 - 160)) / 20 y = (6x - 4 ± √(-4x^2 - 48x - 144)) / 20

Since we're dealing with the square root of a negative value, the solutions for y will be complex numbers. Let's proceed with this solution:

y = (6x - 4 ± √(4) * √(-(x^2 + 12x + 36))) / 20 y = (6x - 4 ± 2i√(x^2 + 12x + 36)) / 20 y = (3x - 2 ± i√(x^2 + 12x + 36)) / 10

Now that we have the solutions for y in terms of x, we can find the product xy:

xy = x * ((3x - 2 ± i√(x^2 + 12x + 36)) / 10)

xy = (3x^2 - 2x ± xi√(x^2 + 12x + 36)) / 10

So, the value of xy can be expressed as (3x^2 - 2x ± xi√(x^2 + 12x + 36)) / 10, depending on the sign of the imaginary term.