Question

(a^2+3 ab +b^2) (7-5b)​

Answer 1

(a²+3ab+b²)(7-5b)=a²×(7-5b)+3ab×(7-5b)+b²×(7-5b)=7a²-5a²b+21b-15ab²+7b²-5b³

Answer 2

To simplify the expression $(a^2 + 3ab + b^2) \cdot (7 - 5b)$, you can use the distributive property (also known as the FOIL method). Distribute each term in the first expression across the terms in the second expression and then combine like terms if possible.

Here's the step-by-step simplification:

$(a^2 + 3ab + b^2) \cdot (7 - 5b)$

Distribute the terms in the first expression: $a^2 \cdot (7 - 5b) + 3ab \cdot (7 - 5b) + b^2 \cdot (7 - 5b)$

Now, apply the distributive property to each term: $7a^2 - 5a^2b + 21ab - 15ab^2 + 7b^2 - 5b^3$

Combining like terms: $7a^2 - 5a^2b + 21ab - 15ab^2 + 7b^2 - 5b^3$

So, the simplified expression is $7a^2 - 5a^2b + 21ab - 15ab^2 + 7b^2 - 5b^3$.