Question

Help (6с-4)^2-(4с+3)^2=0

Answer 1

Ответ:

(6c - 4)² - (4c + 3)² = 0

(6c - 4 - (4c + 3))(6c - 4 + (4c + 3)) = 0

(6c - 4 - 4c - 3)(6c - 4 + 4c + 3) = 0

(2c - 7)(10c - 1) = 0

1) 2c - 7 = 0

2c = 7

c = 7/2 = 3,5

2) 10c - 1 = 0

10c = 1

c = 1/10 = 0,1

Ответ: 0,1 ; 3,5

Объяснение:

Answer 2

Объяснение:

Применяется формула сокращённого умножения: разность квадратов

Answer 3

I see you have an equation that you'd like help with. The equation you've provided is:

(6c - 4)^2 - (4c + 3)^2 = 0

To solve this equation, you can follow these steps:

Step 1: Expand both squared terms. (6c - 4)^2 = (6c - 4)(6c - 4) = 36c^2 - 24c - 24c + 16 = 36c^2 - 48c + 16 (4c + 3)^2 = (4c + 3)(4c + 3) = 16c^2 + 12c + 12c + 9 = 16c^2 + 24c + 9

Step 2: Substitute the expanded terms back into the equation. (36c^2 - 48c + 16) - (16c^2 + 24c + 9) = 0

Step 3: Combine like terms on both sides of the equation. 36c^2 - 48c + 16 - 16c^2 - 24c - 9 = 0

Step 4: Simplify the equation. 20c^2 - 72c + 7 = 0

Now you have a quadratic equation in terms of "c." To solve for "c," you can use the quadratic formula or factoring. Let's use the quadratic formula:

Quadratic formula: c = (-b ± √(b^2 - 4ac)) / 2a

In your equation, a = 20, b = -72, and c = 7.

c = (72 ± √((-72)^2 - 4 * 20 * 7)) / (2 * 20) c = (72 ± √(5184 - 560)) / 40 c = (72 ± √4624) / 40 c = (72 ± 68) / 40

This gives two possible solutions for "c":

1. c = (72 + 68) / 40 = 140 / 40 = 3.5
2. c = (72 - 68) / 40 = 4 / 40 = 0.1

So, the solutions for the equation are c = 3.5 and c = 0.1.