Question

(x-3) (x+4) -(x+6)(x-5); npu=517/29

Answer 1

Объяснение:

$(x-3)(x+4)-(x+6)(x-5)=x^2+x-12-(x^2+x-30)=\\=x^2+x-12-x^2-x+30=18.$

Answer 2

To simplify the expression, let's expand and combine like terms:

(x - 3)(x + 4) - (x + 6)(x - 5)

Expanding the first set of parentheses: = (x * x + x * 4 - 3 * x - 3 * 4) - (x + 6)(x - 5)

Simplifying the expression: = (x^2 + 4x - 3x - 12) - (x^2 - 5x + 6x - 30)

Combining like terms: = (x^2 + x - 12) - (x^2 + x - 30)

Distributing the negative sign in the second set of parentheses: = x^2 + x - 12 - x^2 - x + 30

Simplifying further: = (x^2 - x^2) + (x - x) + (30 - 12)

The x^2 and x terms cancel each other out, leaving: = 0 + 0 + 18

Finally, we have: = 18

Therefore, the simplified expression (x - 3)(x + 4) - (x + 6)(x - 5) is equal to 18.