Question

(y2-2y)2-y2(y+3)(y-3)+2y(2y2+5)=​

Answer 1

Ответ:

(y²-2y)²-y²(y+3)(y-3)+2y(2y²+5) =​ y⁴-4y³+4y²-y⁴+9y²+4y³+10y = 13y²+10y

Answer 2

To solve the given equation, let's simplify it step by step:

Step 1: Expand the expressions within parentheses: (y^2 - 2y)^2 - y^2(y + 3)(y - 3) + 2y(2y^2 + 5)

Expanding the first term: (y^2 - 2y)^2 = (y^2 - 2y)(y^2 - 2y) = y^4 - 4y^3 + 4y^2

Expanding the second term: y^2(y + 3)(y - 3) = (y^2)(y + 3)(y - 3) = y^2(y^2 - 9) = y^4 - 9y^2

Expanding the third term: 2y(2y^2 + 5) = 4y^3 + 10y

Step 2: Substitute the expanded expressions back into the original equation: (y^4 - 4y^3 + 4y^2) - (y^4 - 9y^2) + (4y^3 + 10y)

Simplifying the expression: Canceling out like terms: y^4 - 4y^3 + 4y^2 - y^4 + 9y^2 + 4y^3 + 10y = -y^4 + y^4 - 4y^3 + 4y^3 + 4y^2 + 9y^2 + 10y = 13y^2 + 10y

So, the simplified form of the given equation is 13y^2 + 10y.