Question

(3x-20)(4x+28) (0, 2-0, 06x) =0 ​

Answer 1

Ответ:

x=20/3;

x= -7;

x=10/3;

Объяснение:

3x-20=0  x=20/3 или 4х+28=0 x= -7 или 0,2-0.06х=0 х=0,2/0,06=10/3

Answer 2

To solve the equation $(3x-20)(4x+28)(0, 2-0, 06x) = 0$, we can set each factor equal to zero and solve for $x$ individually.

Setting $3x-20 = 0$: $3x = 20$ $x = \frac{20}{3}$

Setting $4x+28 = 0$: $4x = -28$ $x = -\frac{28}{4}$ $x = -7$

Setting $0,2 - 0,06x = 0$: $0,2 = 0,06x$ $x = \frac{0,2}{0,06}$ $x \approx 3.33$

Therefore, the solutions to the equation $(3x-20)(4x+28)(0, 2-0, 06x) = 0$ are $x = \frac{20}{3}$, $x = -7$, and $x \approx 3.33$.