Question

2+3y-7(5-y)=15 2z-15(1-2z)=7z 8c-(3-7c)=9c+2 1-8(3-7с)=2(1-5z)*3

Answer 1

2+3y-7(5-y)=

15

2z-15(1-2z)=

7z

8c-(3-7c)=

9c+2

1-8(3-7с)=

2(1-5z)*3

2+3y-7(5-y)=

15

2z-15(1-2z)=7z

8c-(3-7c)=9c+2

1-8(3-7с)=2(1-5z)*3

Answer 2

It looks like you've provided a set of equations. Let's solve each equation step by step.

Equation 1: $2 + 3y - 7(5 - y) = 15$ Let's simplify the equation:

$2 + 3y - 35 + 7y = 15$ (Distribute -7) $10y - 33 = 15$ (Combine like terms) $10y = 48$ (Add 33 to both sides) $y = 4.8$ (Divide both sides by 10)

Equation 2: $2z - 15(1 - 2z) = 7z$ Simplify the equation:

$2z - 15 + 30z = 7z$ (Distribute -15) $32z - 15 = 7z$ (Combine like terms) $32z = 22$ (Add 15 to both sides) $z = 0.6875$ (Divide both sides by 32)

Equation 3: $8c - (3 - 7c) = 9c + 2$ Simplify the equation:

$8c - 3 + 7c = 9c + 2$ (Distribute negative sign) $15c - 3 = 9c + 2$ (Combine like terms) $6c = 5$ (Add 3 to both sides) $c = 0.8333$ (Divide both sides by 6)

Equation 4: $1 - 8(3 - 7c) = 2(1 - 5z) \times 3$ Simplify the equation:

$1 - 24 + 56c = 6 - 30z$ (Distribute -8 and 2) $56c - 23 = 6 - 30z$ (Combine like terms) $56c = 29 - 30z$ (Add 23 to both sides) $c = \frac{29 - 30z}{56}$ (Divide both sides by 56)

Please note that the solutions provided for $y$, $z$, and $c$ are in decimal form. If you need fractions or simplified forms, let me know, and I can assist further.