Question

4х²-2ху+х-у=33-4х²+2ху+3х+5у=-37

Answer 1

Ответ:

Непонятно, что это система или два самостоятельных уравнения. Почему не пишут внятно???

Объяснение:

Answer 2

It seems like you've provided a system of two equations with two variables:

1. $4x² - 2xy + x - y = 33$
2. $4x² + 2xy + 3x + 5y = -37$

To solve this system of equations, we can use various methods such as substitution, elimination, or matrix methods. Here, I'll use the elimination method to solve for $x$ and $y$:

First, let's subtract the second equation from the first equation to eliminate the $y$ terms:

$(4x² - 2xy + x - y) - (4x² + 2xy + 3x + 5y) = 33 - (-37)$

Simplifying the left side:

$4x² - 2xy + x - y - 4x² - 2xy - 3x - 5y = 33 + 37$ $4x² - 4x² - 2xy - 2xy + x - 3x - y - 5y = 70$ $-4xy - 4x - 6y = 70$ $-2xy - 2x - 3y = 35$

Now, we have a new equation:

$-2xy - 2x - 3y = 35$

Let's solve this equation for $y$:

$y = -\frac{2x + 35}{3}$

Now that we have the value of $y$ in terms of $x$, we can substitute it into either of the original equations to solve for $x$. Let's use the first equation:

$4x² - 2x\left(-\frac{2x + 35}{3}\right) + x - \left(-\frac{2x + 35}{3}\right) = 33$

Simplify the equation:

$4x² + \frac{4x² + 70x}{3} + x + \frac{2x + 35}{3} = 33$

Multiply through by 3 to eliminate fractions:

$12x² + 4x² + 70x + 3x + 2x + 35 = 99$

Combine like terms:

$16x² + 75x + 35 = 99$

Subtract 99 from both sides:

$16x² + 75x - 64 = 0$

This is a quadratic equation that can be factored or solved using the quadratic formula. However, the solutions for $x$ might involve complex numbers.

After solving for $x$, you can substitute the value of $x$ back into the equation for $y$ to find the corresponding values of $y$. Keep in mind that these equations appear to be quite complicated, and the solutions might involve complex numbers or other intricate mathematical expressions.