Question

3-3 а при а=1, а= -1 3х + 5у при х=0,3 у = 1,2 ; у= -0,3

Answer 1

Ответ:

3-3а

3-3*1=0

3-3*(-1)=6

3x+5y

3*0.3+5*1.2=6.9

3*0.3+5*(-0.3)=2.4

Answer 2

To find the values of 3x + 5y for the given combinations of x and y, we can substitute the given values into the equation.

1. When a = 1: Substituting a = 1 into the equation 3x + 5y: 3x + 5y = 3(0) + 5(1.2) = 0 + 6 = 6

   Substituting a = -1 into the equation 3x + 5y: 3x + 5y = 3(0) + 5(-0.3) = 0 - 1.5 = -1.5

2. When a = -1: Substituting a = 1 into the equation 3x + 5y: 3x + 5y = 3(0) + 5(1.2) = 0 + 6 = 6

   Substituting a = -1 into the equation 3x + 5y: 3x + 5y = 3(0) + 5(-0.3) = 0 - 1.5 = -1.5

Therefore, for the given values of a and x, the values of 3x + 5y are:

• When a = 1:

  • For x = 0 and y = 1.2: 3x + 5y = 6
  • For x = 3 and y = 1.2: 3x + 5y = 6
  • For x = 0 and y = -0.3: 3x + 5y = -1.5

• When a = -1:

  • For x = 0 and y = 1.2: 3x + 5y = 6
  • For x = 3 and y = 1.2: 3x + 5y = 6
  • For x = 0 and y = -0.3: 3x + 5y = -1.5