Question

A²-b² a=√6-3 b=√6*13

Answer 1

Ответ:

-999-6√6

Объяснение:

a²-b²= (а-b) (a+b) =  (√6-3)² -(√6*13)²= (√6-3-√6*13)(√6-3+√6*13)=

=(-3-12√6) (-3+14√6)= 9-42√6+36√6-1008= -999-6√6

Answer 2

It seems like you want to calculate the value of $a^2 - b^2$ where $a = \sqrt{6} - 3$ and $b = \sqrt{6} \cdot 13$. Let's break down the calculation step by step:

1. Calculate $a^2$: $a^2 = (\sqrt{6} - 3)^2$ $a^2 = 6 - 6\sqrt{6} + 9$ $a^2 = 15 - 6\sqrt{6}$

2. Calculate $b^2$: $b^2 = (\sqrt{6} \cdot 13)^2$ $b^2 = 6 \cdot 169$ $b^2 = 1014$

3. Calculate $a^2 - b^2$: $a^2 - b^2 = (15 - 6\sqrt{6}) - 1014$ $a^2 - b^2 = -999 - 6\sqrt{6}$

So, $a^2 - b^2$ is approximately $-999 - 6\sqrt{6}$.