Question

1) (х-4)(1+х)=0 2) (4+|х|)(|х|-1)=0 решите уравнения

Answer 1

Ответ:

1) x¹= -1. x²= 4

2) x¹= -1. x²= 1

Answer 2

1. (х-4)(1+х) = 0

To solve this equation, we set each factor equal to zero and solve for x:

Setting х - 4 = 0: х = 4

Setting 1 + х = 0: х = -1

So the solutions to the equation (х-4)(1+х) = 0 are x = 4 and x = -1.

2. (4 + |х|)(|х| - 1) = 0

To solve this equation, we consider two cases:

Case 1: (4 + |х|) = 0 Solving for |х|: |х| = -4 Since absolute value cannot be negative, there are no solutions in this case.

Case 2: (|х| - 1) = 0 Solving for |х|: |х| = 1 This equation has two solutions: |х| = 1, which means х = 1 or х = -1.

Therefore, the solutions to the equation (4 + |х|)(|х| - 1) = 0 are x = 1 and x = -1.