Question

A^2-5/2+a ,если а = -3

Answer 1

$\dfrac{a^2-5}{2+a} ~~~~|~~ a = -3\\\\\\\dfrac{(-3)^2-5}{2+(-3)} = \dfrac{9-5}{2-3} = \dfrac{4}{-1} = -4$

Answer 2

To evaluate the expression $A^2 - \frac{5}{2} + a$ when $a = -3$, we substitute the value of $a$ into the expression:

Given expression: $A^2 - \frac{5}{2} + a$

Substitute $a = -3$: $A^2 - \frac{5}{2} + (-3)$

Now, simplify the expression:

$A^2 - \frac{5}{2} - 3$

To perform the subtraction, convert the fraction to have a common denominator: $A^2 - \frac{10}{4} - \frac{12}{4}$

Combine the fractions: $A^2 - \frac{22}{4}$

Simplify the fraction: $A^2 - \frac{11}{2}$

So, the expression $A^2 - \frac{5}{2} + a$ with $a = -3$ simplifies to $A^2 - \frac{11}{2}$.