Question

-0,6x^2-2/1-2y при x=-2 y=0.3

Answer 1

Ответ:1,2^2-11/10

Объяснение:

Answer 2

Ответ:

-11

Объяснение:

-0,6x²-2/1-2y                          при x=-2 y=0.3

-0,6x^²-2 / 1-2y   =(-0,6*(-2)²-2)/(1-2*(0,3)=  (0,6*4-2)/(1-0,6)=   (-4,2-2)/0,4=

=-4,4 / 0,4=-11

Answer 3

To evaluate the expression -0.6x^2 - (2/(1 - 2y)) when x = -2 and y = 0.3, we substitute these values into the expression:

-0.6(-2)^2 - (2/(1 - 2(0.3)))

First, we calculate the value of -2^2, which is 4:

-0.6(4) - (2/(1 - 2(0.3)))

Next, we calculate the value of 2(0.3), which is 0.6:

-0.6(4) - (2/(1 - 0.6))

Now we calculate the value of (1 - 0.6), which is 0.4:

-0.6(4) - (2/0.4)

Next, we simplify the expression inside the parentheses:

-2.4 - (2/0.4)

Now we calculate the value of 2/0.4, which is 5:

-2.4 - 5

Finally, we subtract 5 from -2.4:

-7.4

Therefore, when x = -2 and y = 0.3, the expression -0.6x^2 - (2/(1 - 2y)) evaluates to -7.4.