Question

A-2в/x+c * 3x+3c/5a-10в​

Answer 1

$\tt\displaystyle\frac{a-2b}{x+c} \cdot \frac{3x+3c}{5a-10b} = \frac{a-2b}{x+c}\cdot\frac{3(x+c)}{5(a-2b)} = \\\\\\=\frac{1}{1}\cdot\frac{3\cdot1}{5\cdot1} =1\cdot \frac{3}{5} = \frac{3}{5}$

Answer 2

To simplify the expression (A - 2B)/(x + C) * (3x + 3C)/(5A - 10B), let's break it down step by step:

1. Factor out the common terms: (A - 2B)/(x + C) can be written as (A - 2B)/(1(x + C)) since anything divided by 1 is itself.

2. Simplify the expression: (A - 2B)/(1(x + C)) * (3x + 3C)/(5A - 10B) = (A - 2B)(3x + 3C)/(1(x + C))(5A - 10B)

3. Cancel out common factors: Notice that (A - 2B) can be canceled out with (5A - 10B): = (A - 2B)(3x + 3C)/(1(x + C))(5A - 10B) = (3x + 3C)/(1(x + C))

Therefore, the simplified expression is (3x + 3C)/(x + C).