Question

-2x²+x+15=020 баллов даю​

Answer 1

Ответ:

Объяснение:

На фото

Answer 2

To solve the quadratic equation -2x² + x + 15 = 0 and find the values of x, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this case, a = -2, b = 1, and c = 15. Plugging these values into the formula, we get:

x = (-(1) ± √((1)² - 4(-2)(15))) / (2(-2)) x = (-1 ± √(1 + 120)) / (-4) x = (-1 ± √121) / (-4) x = (-1 ± 11) / (-4)

So, the two solutions for x are:

x₁ = (-1 + 11) / (-4) = 10 / (-4) = -2.5 x₂ = (-1 - 11) / (-4) = -12 / (-4) = 3

Therefore, the solutions to the equation -2x² + x + 15 = 0 are x = -2.5 and x = 3.

Please note that the equation you provided doesn't seem to match a quadratic equation since it's set equal to 20 rather than 0. However, I have solved it as if it were a quadratic equation. If you meant something different, please provide more information or clarify the equation.